array - c - c - Whine Column A - Column B Whlinea -sin 90- A - i - cos - A II hlineb -tan 90- A - ii - cosec - A IIlhlinec sec90-A -iii cot A lllhline lendarrayA- i - a - ii - c- iii-bB- i -a- ii -b- iii - cC- i -c- ii -a- iii - bD- i - b - ii - c - iii - a

The correct option is A (i) – a , (ii) – c , (iii) b sin(90 – A ) = cosA tan(90 – A) = cotA sec(90 – A) = cosecA ...

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Byju's Answer

Standard X

Mathematics

Complementary Trigonometric Ratios

array | c | c...

Question

$\begin{matrix} C o l u m n A & C o l u m n B (a) s i n (90 - A) & (i) c o s A (b) t a n (90 - A) & (i i) c o s e c A (c) s e c (90 - A) & (i i i) c o t A \end{matrix}$

(i) – a , (ii) – b, (iii) - c

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(i) – a , (ii) – c , (iii) - b

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(i) – b , (ii) – c , (iii) - a

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(i) – c, (ii) – a , (iii) - b

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Solution

The correct option is B
(i) – a , (ii) – c , (iii) - b

sin(90 – A ) = cosA

tan(90 – A) = cotA

sec(90 – A) = cosecA

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Column AColumn B(a) sin(90−A)(i) cos A(b) tan(90−A) (ii) cosec A(c) sec(90−A)(iii) cot A

The correct option is B (i) – a , (ii) – c , (iii) - b sin(90 – A ) = cosA tan(90 – A) = cotA sec(90 – A) = cosecA

$\begin{matrix} C o l u m n A & C o l u m n B (a) s i n (90 - A) & (i) c o s A (b) t a n (90 - A) & (i i) c o s e c A (c) s e c (90 - A) & (i i i) c o t A \end{matrix}$

The correct option is B
(i) – a , (ii) – c , (iii) - b

sin(90 – A ) = cosA

tan(90 – A) = cotA

sec(90 – A) = cosecA