$\begin{matrix} F i n a n c e & M a r k e t i n g & S o f t w a r e & O t h e r s 1992 & 12 & 36 & 19 & 33 1993 & 17 & 48 & 23 & 12 1994 & 23 & 43 & 21 & 13 1995 & 19 & 37 & 16 & 28 1996 & 32 & 32 & 20 & 16 \end{matrix}$

$\begin{matrix} F i n a n c e & M a r k e t i n g & S o f t w a r e 1992 & 5450 & 5170 & 5290 1993 & 6380 & 6390 & 6440 1994 & 7550 & 7630 & 7050 1995 & 8920 & 8960 & 7760 1996 & 9810 & 10220 & 8640 \end{matrix}$
The number of students who got jobs in finance is less than the number of students getting marketing jobs, in the first 3 years, by

826

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650

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598

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548

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Solution

The correct option is C
598

(24% of 800)+ (31% of 600)+ (20% of 1100) = 598

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Similar questions

Q. Find the arithmetic mean of each of the following frequency distributions using step-deviation method:

Class	Number of students
4-8	2
8-12	12
12-16	15
16-20	25
20-24	18
24-28	12
28-32	13
32-36	3

Q. The marks obtained out of 40 by the 20 students were as follows.

Find the mean of the marks.

Following table gives marks and number of students of a class.

Which point on the frequency polygon will have its y coordinate as 19?

Q. Marks obtained by 24 students in English and Statistics in a class are given below . Prepare two-way frequency distribution table.

S.No	1	2	3	4	5	6	7	8	9	10	11	12
Marks in English	22	23	23	23	23	24	23	25	22	23	24	24
Marks in Statistics	16	16	18	16	16	17	16	19	16	18	18	17

S.No	13	14	15	16	17	18	19	20	21	22	23	24
Marks in English	23	25	23	22	27	27	26	28	25	24	23	25
Marks in Statistics	16	17	17	17	15	16	18	19	19	16	17	19

The ages of $20$ husbands and wives are given below. Form a two-way frequency table showing the relationship between the ages of husbands and wives with the class-intervals $20 - 25, 25 - 30$ etc.

$\begin{matrix} S.No & Age of Husband & Age of Wife 1 & 28 & 23 2 & 37 & 30 3 & 42 & 40 4 & 25 & 26 5 & 29 & 25 6 & 47 & 31 7 & 37 & 35 8 & 35 & 25 9 & 23 & 21 10 & 41 & 38 11 & 27 & 24 12 & 39 & 34 13 & 23 & 20 14 & 33 & 31 15 & 36 & 29 16 & 32 & 35 17 & 22 & 23 18 & 29 & 27 19 & 38 & 34 20 & 48 & 47 \end{matrix}$

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The correct option is C 598(24% of 800)+ (31% of 600)+ (20% of 1100) = 598

The correct option is C
598

(24% of 800)+ (31% of 600)+ (20% of 1100) = 598