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Concentration of SO2(in ppm)Number of days (frequency)0.000.0440.040.0890.080.1290.120.1620.160.2040.200.242Total30
The above frequency distribution table represents the concentration of Sulphur dioxide in the air in parts per million of a certain city for 30 days. Using this table,
find the probability of the concentration of Sulphur dioxide in the interval 0.12−0.16 on any of these days.

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Solution

Total number of days =30
Number of days for which the concentration of Sulphur dioxide was in the interval of 0.12 −0.16= 2

P(concentration of Sulphur dioxide in the interval 0.12 - 0.16)=Number of days for which the concentration of Sulphur dioxide was in the interval of 0.12 - 0.16Total number of days
Hence, required probability, P=230=115

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