Question

$\begin{array}{ccccc}\text{Outcome}& 2& 3& 5& 6\\ \text{Frequency}& 10& 14& 16& 20\end{array}$

A dice was thrown 80 times and the frequency of occurrence of 2, 3, 5 and 6 is given in the table. What is the probability of occurrence of 1 or 4?

• A. 1
• B. 0.67
• C. 0.25
• D. $\frac{1}{4}$

Answer 1

Answer: (C), (D)

The correct options are
C

0.25

D

$\frac{1}{4}$

Total frequency of occurrence of 2, 3, 5 and 6 = 60.

Frequency of occurrence of 1 or 4 = 80 - 60 = 20.

Probability of occurrence of 1 or 4 = $\frac{\text{Frequency of occurrence of 1 or 4}}{\text{Total number of times die is thrown}}$

So, probability of occurrence of 1 or 4 = $\frac{20}{80}$ = $\frac{1}{4}$ = 0.25