Question

$\begin{array}{cccc}& \text{Column - I}& \text{Column -II}& \\ \text{(I)}& \text{The number of the circles touching the}& \text{(P)}& 1\\ & \text{given three non-concurrent lines}& & \\ \text{(II)}& \text{The number of circles touching}y=x\text{at}& \text{(Q)}& 2\\ & (2,2)\text{and also touching the line}x+2y=4& & \\ \text{(III)}& \text{The number of circles touching the lines}& \text{(R)}& 4\\ & x\pm y=2\text{and passing through the point}(4,3)& & \\ \text{(IV)}& \text{The number of circles intersecting the}& \text{(S)}& \infty \\ & \text{given three circles orthogonally}& & \\ & & \text{(T)}& 5\\ & & \text{(U)}& 3\end{array}$

Which of the following is the only CORRECT combination?

• A. $\text{I}\to \text{R}$
• B. $\text{II}\to \text{T}$
• C. $\text{III}\to \text{U}$
• D. $\text{IV}\to \text{S}$

Answer 1

The correct option is A $\text{I}\to \text{R}$

$a.$

$b.$
$c.$

$d.$
The number of circle is $1$ that can intersect with the given three circles orthogonally