Question

$\begin{array}{c}EB=DB\\ AE=BC\\ \angle A=\angle C={90}^{\circ }\\ So,\Delta ABE\cong \Delta CDB\end{array}$

Which congruence criterion do you use in the following?

• A. RHS
• B. AAA
• C. ASA
• D. SSS

Answer 1

The correct option is A RHS

In $△ABE$ and $△CBE$, we have

$\angle A=\angle C$

$EB=DB$

And $EB=DB$

$\therefore$ By $RHS$ congruency rule $△ABE$ and $△CDB$ are congruent.

So, $A$ is correct option.