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Question

# Column IColumn II(A) If v (frequency) is increased keepingI (intensity) and Φ(work function) constant(P) Stoping potential increases(B)If I is increased keeping v and Φ constant(Q) Saturation photocurrent increases(C) If the distance between anode and cathode increases.(R) Maximum KE of the photoelectrons increase(D) If Φ is decreased keeping v and I constant(S) Stopping potential remains the same

A

(A) (P,R); (B) (Q,S); (C) (S); (D) (P,R)

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B

(A) (Q,S); (B) (P,R); (C) (S); (D) (P,R)

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C

(A) (P,R); (B) (Q,S); (C) (P,R); (D) (S)

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D

(A) (P,R); (B) (S); (C) (Q,S); (D) (P,R)

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Solution

## The correct option is A (A) (P,R); (B) (Q,S); (C) (S); (D) (P,R) From eV0=hv−Φ and Kmax=hv−Φ. If v increases keeping Φ constant, then V0 and Kmax both increase. If Φ decreases keeping v constant, then V0 and Kmax increase. If I increases, more photoelectrons would be liberated, hence saturation photocurrent increases. If the separation between cathode and anode is increased, then there is no effect on V0, Kmax or current

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