beginarray - hline Substance-Amount Initially filtered out of bloodstream-Amount returned to bloodstreamillhline Water- 100L- 99LIllhlineGlucose- 370 g- 364 g lllhline Urea- 30g- 10gllihline array Calculate the amount of each substance left in the urine-A- Water -1 L- Glucose -6 g- Urea -2 gB- Water -2 L- Glucose -6 g- Urea -50 gC- Water -1 L- Glucose -6 g- Urea -20 gD- Water -11 L- Glucose -60 g- Urea -2 g

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Byju's Answer

Standard IX

Biology

Homeostasis

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Question

$\begin{matrix} S u b s t a n c e & A m o u n t I n i t i a l l y f i l t e r e d o u t o f b l o o d s t r e a m & A m o u n t r e t u r n e d t o b l o o d s t r e a m W a t e r & 100 L & 99 L G l u c o s e & 370 g & 364 g U r e a & 30 g & 10 g \end{matrix}$

Calculate the amount of each substance left in the urine.

Water = 1L, Glucose = 6g, Urea = 2g

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Water = 2L, Glucose = 6g, Urea = 50g

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Water = 1L, Glucose = 6g, Urea = 20g

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Water = 11L, Glucose = 60g, Urea = 2g

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Solution

The correct option is C
Water = 1L, Glucose = 6g, Urea = 20g

From the given formula,

Amount in urine = Amount initially filtered out of bloodstream - Amount returned to the bloodstream

1. Amount in urine (Water) = 100 - 99 = 1L

2. Amount in urine (Glucose) = 370 - 364 = 6g

3. Amount in urine (Urea) = 30 - 10 = 20g

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Similar questions

$\begin{matrix} S u b s t a n c e & A m o u n t I n i t i a l l y f i l t e r e d o u t o f b l o o d s t r e a m & A m o u n t r e t u r n e d t o b l o o d s t r e a m W a t e r & 100 L & 99 L G l u c o s e & 370 g & 364 g U r e a & 30 g & 10 g \end{matrix}$

Calculate the percentage of each substance absorbed into the blood.

Percent absorbed by blood = $\frac{A m o u n t r e t u r n e d t o b l o o d s t r e a m \times 100}{A m o u n t i n i t i a l l y f i l t e r e d o u t}$

Match the following based on the composition of urine.

$\begin{matrix} S . N o & S u b s t a n c e & U r i n e 1 & W a t e r & a .0 2 & G l u c o s e & b .2 3 & U r e a & c . 0.6 4 & S a l t & d .95 \end{matrix}$

Q. Following are four statements. Find out the correct combination.
1. Glucose has high threshold value.
2. Urine is concentrated in Henles loop.
3. Haemodialyser removes urea, uric acid, glucose and proteins.
4. In glomerulus, urea, uric acid, water, glucose and plasma proteins are filtered out

18 g

glucose and

6 g

urea are dissolved in

1

litre aqueous solution at

27^{o} C .

The osmotic pressure of the solution will be___________.

Match the following:

$\begin{matrix} Column I & Column II i. Pressure filtration & a. Urea and uric acid ii. Selective reabsorption & b. Penicillin iii. Tubular secretion & c. Water, glucose, amino acids iv. Excretion & d. Water, glucose, urea \end{matrix}$

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SubstanceAmount Initially filtered out of bloodstreamAmount returned to bloodstreamWater 100L 99LGlucose 370g 364gUrea 30g 10g Calculate the amount of each substance left in the urine.