$\begin{matrix} A & B A_{1} & B_{1} A_{2} & B_{2} \end{matrix}$

If A and B are in inverse proportion, then which of the following is true?

A_{1} \times A_{2} = B_{1} \times B_{2}

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A_{1} \times B_{1} = A_{2} \times B_{2}

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\frac{A_{1}}{B_{1}} = \frac{B_{2}}{A_{2}}

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\frac{A_{1}}{B_{2}} = \frac{B_{2}}{A_{1}}

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Solution

The correct option is B $A_{1} \times B_{1} = A_{2} \times B_{2}$
If A and B are in inverse proportion,

$\frac{A_{1}}{A_{2}} = \frac{B_{2}}{B_{1}}$

$\Rightarrow A_{1} \times B_{1} = A_{2} \times B_{2}$

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