Question

$\begin{array}{cc}\text{Column-I}& \text{Column-II}\\ \text{(i) For a particle moving in a circle}& \text{(a)}\text{The accleration may be perpendicular to its velocity}\\ \text{(ii) For a particle moving in a straight line}& \text{(b)}\text{The acceleration may be in the direction of velocity}\\ \text{(iii) For a particle undergoing projectile motion with angle of projection}\alpha ;0\le \alpha \le \frac{\pi }{2}& \text{(c)}\text{The acceleration may be at some angle}\\ & \theta (0\le \theta \le \frac{\pi }{2})\text{with the velocity}\\ \text{(iv) For a particle is moving in space}& \text{(d)}\text{The acceleration may be opposite to velocity}\end{array}$

• A. i-a,b, ii-b, iii-a,c, iv-a,b,c,d
• B. i-a,c, ii-b,d iii-a,c, iv-a,b,c,d
• C. i-a,b, ii-b iii-a,c, iv-a,b,c,d
• D. i-a,b, ii-b,d iii-a,c, iv-a,b,c,d

Answer 1

The correct option is B i-a,c, ii-b,d iii-a,c, iv-a,b,c,d

i. In the uniform circular motion, the acceleration and the velocity are perpendicular to each other, but in non uniform circular motion the angle between the velocity and the acceleration lies between $0$ to $\pi /2$.
ii. In a straight line motion, the acceleration vector and the velocity vector are collinear to each other, i.e., the angle between them is either $0$ or ${180}^{\circ }$
iii. In a projectile motion, the angle $\left(\theta \right)$ between th velocity and the acceleration can vary from $0<\theta <\pi$
iv. In space angle between velocity and acceleration may be $0\le \theta \le \pi$