Question

$\begin{array}{cc}\text{List I}& \text{List II}\\ \text{1. Plaster of Paris}& \text{a.}CaS{O}_4.2H_{2}O\\ \text{2. Epsomite}& \text{b.}CaS{O}_4.1/2H_{2}O\\ \text{3. Kieserite}& \text{c.}MgS{O}_4.7H_{2}O\\ \text{4. Gypsum}& \text{d.}MgS{O}_4.H_{2}O\\ & \text{e.}CaS{O}_4\end{array}$

• A. 1 - a; 2 - b; 3 - c; 4 - e
• B. 1 - b; 2 - c; 3 - d; 4 - a;
• C. 1 - b; 2 - d; 3 - c; 4 - a;
• D. 1 - a; 2 - c; 3 - d; 4 - b;

Answer 1

The correct option is B

1 - b; 2 - c; 3 - d; 4 - a;

Gypsum is the di-hydrate of calcium sulphate. Plaster of Paris is of calcium sulphate hemihydrate. Epsomite is $MgS{O}_4.7H_{2}O$

Kieserite is $MgS{O}_4.H_{2}O$