begin array -text A N - F - O - Li - t e x t P Increasing order of - EA - hlineendarray Which of the following is the only CORRECT combination-A- A-S- B-R- C-P- D-QB- A-S- B-Q- C-Q- D-PC- A-R- B-S- C-Q- D-PD- A-P- B-Q- C-R- D-S

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Trend in Ionisation Enthalpy

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Question

$\begin{matrix} List I & List II (A) N, F, O, Li & (P) Increasing order of |EA| (B) F, N, Si, Mg, Rb & (Q) Increasing order of {IE}_{1} (C) K, Na, Al, Mg & {(R) Increasing order of IE}_{2} (D) N, B, O, Cl & (S) Incresing order of radius \end{matrix}$
Which of the following is the only CORRECT combination?

A-S; B-R; C-P; D-Q

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A-S; B-Q; C-Q; D-P

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A-R; B-S; C-Q; D-P

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A-P; B-Q; C-R; D-S

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Solution

The correct option is C A-R; B-S; C-Q; D-P
(A) Ionisation energy increases from left to right in a period due to increase in effective nuclear charge which bound the outermost electrons strongly. However, due to noble gas configuration of $(L i^{+} : 1 s^{2})$ , it has the highest second ionization energy followed by $(O^{+} : 2 s^{2} 2 p^{3})$ which has half filled electronic configration. Hence, $I E_{2}$ for the given elements follows the order: $N < F < O < L i$

(B) On moving along the group from top to bottom atomic radius increases and while moving left to right in a preriod it decreases. Hence the radius follows the order: $F < N < S i < M g < R b$

(C) Ionisation energy decreases down the group due to increase in number of shells and increases as we move from left to right. However due to filled electronic configuration of $M g$ , its IE will be greater than $A l$ .
$K < N a < A l < M g$

(D) $E A$ refers the amount of energy released when an electron is added to a neutral atom. Electron affinity increases as we move from left to right along a period. However, due to half filled configuration, $N$ has the least EA. So correct order of electron affinity will be: $N < B < O < C l$

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List IList II(A) N, F, O, Li(P) Increasing order of |EA|(B) F, N, Si, Mg, Rb(Q) Increasing order of IE1(C) K, Na, Al, Mg(R) Increasing order of IE2(D) N, B, O, Cl(S) Incresing order of radius Which of the following is the only CORRECT combination?