Question

$\begin{array}{cccc}& \text{Column-I}& & \text{Column-II}\\ \text{(a)}& ICl& \text{(p)}& \text{Linear}\\ \text{(b)}& Br{F}_2^{+}& \text{(q)}& \text{Angular}\\ \text{(c)}& Cl{F}_4^{-}& \text{(r)}& \text{Tetrahedral}\\ \text{(d)}& AlC{l}_4^{-}& \text{(s)}& \text{Square planar}\end{array}$

• A. $\left(a\right)\to \left(p\right);\left(b\right)\to \left(q\right);\left(c\right)\to \left(s\right);\left(d\right)\to \left(r\right)$
• B. $\left(a\right)\to \left(q\right);\left(b\right)\to \left(p\right);\left(c\right)\to \left(s\right);\left(d\right)\to \left(r\right)$
• C. $\left(a\right)\to \left(p\right);\left(b\right)\to \left(q\right);\left(c\right)\to \left(r\right);\left(d\right)\to \left(s\right)$
• D. $\left(a\right)\to \left(q\right);\left(b\right)\to \left(p\right);\left(c\right)\to \left(r\right);\left(d\right)\to \left(s\right)$

Answer 1

The correct option is A $\left(a\right)\to \left(p\right);\left(b\right)\to \left(q\right);\left(c\right)\to \left(s\right);\left(d\right)\to \left(r\right)$

We could get to the solution by applying the valence shell electron pair repulsion theory on molecules.

But $ICl$ has only two atoms and since there is just a single sigma bond between the halogen atoms, it will be linear.

From the other options, since we are only required to get the shapes, $Br{F}_2^{+}$ has to be bent. No other molecule (from the given) shall correspond to this shape. The following is square planar: