Question

$\begin{array}{cccc}& \text{List - I}& & \text{List - II}\\ \text{(P)}& \text{Very dilute solution of HCl}& \text{(1)}& O_2\text{evolved at anode}\\ \text{(Q)}& \text{Very dilute solution of KCl}& \text{(2)}& H_2\text{evolved at cathode}\\ \text{(R)}& \text{Concentrated solution of NaCl}& \text{(3)}& C{l}_2\text{evolved at anode}\\ \text{(S)}& \text{Fairly concentrated solution of}AgN{O}_3& \text{(4)}& \text{Na deposition at cathode}\\ & & \text{(5)}& \text{Ag deposition at cathode}\\ & & \text{(6)}& \text{K deposition at cathode}\end{array}$
Match each product in LIST-I with one or more reaction in LIST-II and choose the correct option.

• A. $P\to 1,2;Q\to 1,2;R\to 2,3;S\to 1,5$
• B. $P\to 1,2;Q\to 2,3;R\to 2,3;S\to 1,5$
• C. $P\to 2,3;Q\to 3,6;R\to 3,4;S\to 1,5$
• D. $P\to 2,3;Q\to 3,6;R\to 2,3;S\to 2,5$

Answer 1

The correct option is A $P\to 1,2;Q\to 1,2;R\to 2,3;S\to 1,5$

(P) At Cathode: $2H^{+}+2e^{-}\to H_2\left(g\right)$

At anode : (since it is a very dilute solution):
$4{\mathrm{OH}}^{-}\to O_2+2H_{2}O+4e^{-}$
(Q)
At Cathode: $2H^{+}+2e^{-}\to H_2\left(g\right)$

At anode : (since it is a very dilute solution):
$4{\mathrm{OH}}^{-}\to O_2+2H_{2}O+4e^{-}$
(R)
At Cathode: $2H^{+}+2e^{-}\to H_2\left(g\right)$

At anode : (since it is a concentrated solution):
$2{\mathrm{Cl}}^{-}\to {\mathrm{Cl}}_2+2e^{-}$
(S)
At Cathode: $A{g}^{+}+e^{-}\to \mathrm{Ag}\left(s\right)$

At anode :
$4{\mathrm{OH}}^{-}\to O_2+2H_{2}O+4e^{-}$