$\begin{matrix} (3 x - 2 y) (2 x + y) = \end{matrix}$

= 6 x^{2} - x y + 2 y^{2}

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= 6 x^{2} + x y - 2 y^{2}

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= 6 x^{2} - x y - 2 y^{2}

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= 6 x^{2} + x y + 2 y^{2}

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Solution

The correct option is C $= 6 x^{2} - x y - 2 y^{2}$
Part (1)

$(a - 2) (a + 2)$

$a^{2} - 4$

Part (2)

$(3 x - 2 y) (2 x + y)$

$= 6 x^{2} + 3 x y - 4 x y - 2 y^{2}$

$= 6 x^{2} - x y - 2 y^{2}$
Hence, this is the answer.

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