You visited us 2 times! Enjoying our articles? Unlock Full Access!

Definition of Function

[ ; 3x - 2y 2...

Question

$\begin{matrix} (3 x - 2 y) (2 x + y) = \end{matrix}$

= 6 x^{2} - x y + 2 y^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

= 6 x^{2} + x y - 2 y^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

= 6 x^{2} - x y - 2 y^{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

= 6 x^{2} + x y + 2 y^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $= 6 x^{2} - x y - 2 y^{2}$
Part (1)

$(a - 2) (a + 2)$

$a^{2} - 4$

Part (2)

$(3 x - 2 y) (2 x + y)$

$= 6 x^{2} + 3 x y - 4 x y - 2 y^{2}$

$= 6 x^{2} - x y - 2 y^{2}$
Hence, this is the answer.

Suggest Corrections

Similar questions

(3 x - 2 y) (2 x + y)

6 x^{2} - x y - 2 y^{2}

2 x^{2} y^{2} - 5 x y + y^{2}

2 y^{2} + 6 x^{2} y^{2} - x y

6 x^{2} - 3 x y + 4 y^{2}

2 y^{2} + x y - 4 x^{2}

Let A = 3 y^{2} + 9 x - 3 x^{2}, B = 6 x^{2} - 2 y^{2} + 3 x, C = 9 x^{2} - 3 x y - y^{2} . Find A + B - C.

3 x^{2}

- 5 x y

+ 2 y^{2} = 0

6 x^{2} - x y + k y^{2} = 0

k^{2} + 7 k - 10

=

Join BYJU'S Learning Program