Question

Simplify:
$\frac{{\left(2^5\right)}^2\times 7^3}{8^3\times 7}$

Answer 1

$\frac{{\left(2^5\right)}^2\times 7^3}{8^3\times 7}$
$=\frac{2^{10}\times 7^3}{{\left(2^3\right)}^3\times 7}$ [$\because (a^m{)}^n=a^{m\times n}$]
$=\frac{2^{10}\times 7^3}{2^9\times 7}$

$=2^{(10-9)}\times 7^{(3-1)}$ [$\because a^m÷a^n=a^{m-n}$]

$=2^1\times 7^2$
$=2\times 49$
$=98$

Hence, $\frac{{\left(2^5\right)}^2\times 7^3}{8^3\times 7}=98$