The correct option is A 10
Given, ⎡⎢⎣1020302045803080171⎤⎥⎦=⎡⎢⎣100210341⎤⎥⎦⎡⎢⎣x00050001⎤⎥⎦⎡⎢⎣123014001⎤⎥⎦
⇒⎡⎢⎣1020302045803080171⎤⎥⎦=⎡⎢⎣x002x503x201⎤⎥⎦⎡⎢⎣123014001⎤⎥⎦
⇒⎡⎢⎣1020302045803080171⎤⎥⎦=⎡⎢⎣x2x3x2x4x+56x+203x6x+209x+81⎤⎥⎦
On comparing, we get x=10