${[\begin{matrix} - C H_{2} - C H ∣ O H - C H_{2} - C H ∣ O H - C H_{2} - C H ∣ O H - \end{matrix}]}_{n}$
Polyvinyl alcohol (as shown above) is a unique polymer having high affinity for water. Which of the following procedures would be most suitable for its preparation?

radical chain polymerisation of

C H_{2} = C H - C H_{2} - O H

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radical chain polymerisation of

C H_{2} = C H - O H

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radical chain polymerisation of

C H_{2} = C H - C O_{2} C H_{3}

, following by base catalysed hydrolysis

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radical chain polymerisation of

C H_{2} = C H - O C O C H_{3}

, followed by acid catalysed hydrolysis

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radical chain polymerisation of

C H_{2} = C H - O C O C H_{3}

, followed by base catalysed hydrolysis

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Solution

The correct option is A radical chain polymerisation of $C H_{2} = C H - O H$
${[\begin{matrix} - C H_{2} - C H ∣ O H - C H_{2} - C H ∣ O H - C H_{2} - C H ∣ O H - \end{matrix}]}_{n}$

Polyvinyl alcohol is prepared by radical chain polymerisation of $C H_{2} = C H - O C O C H_{3}$ , followed by base catalysed hydrolysis in which acetate group is replaced by hydroxide group.

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Similar questions

C H_{3} - C | C H_{3} H - C H_{2} - C H_{2} - O H

C H_{3} - O H | C | C H_{3} - C H_{2} - C H_{3}

C H_{3} C H_{3} | C H - O H | C H - C H_{3}

A, B, C

C H_{3} - C H_{2} - C H_{2} - O H

C H_{3} - C H = C H - O H

C H_{3} - C H = C H - C H_{2} - O H

C H_{3} - C H = C H - O H

C H_{3} - C H = C H - C H_{2} - O H | C H - C H_{3} ⟶ C H_{3} - C H = C H - C H_{2} - C O O H

C H_{3} - C H_{2} - O H | C H - C H_{2} - C H_{2} - C H_{2} - C H_{2} - C H_{2} - C H_{2} - C H_{2} - C H_{2} - C H_{3} | C H - C H_{3}

C H_{3} - C H = C H - C H_{2} - O | | C - C H_{3} \to C H_{3} - C H = C H - C H_{2} - O | | C - O H

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