$\begin{matrix} 15 & (120) & 16 12 & (108) & 18 13 & (. . . .) & 14 \end{matrix}$

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104

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Solution

The correct option is A 91
The number in the first column multiplied by half the number in the third column is equal to the number in the second column.
Thus,
$15 \times \frac{16}{2} = 120$
$12 \times \frac{18}{2} = 108$
$13 \times \frac{14}{2} = 91$

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