$\begin{matrix} 15 & 90 & 24 28 & 112 & 16 17 & . . . . & 16 \end{matrix}$

55

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68

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78

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99

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Solution

The correct option is D $68$
Multiply the numbers in first and third column and divide by 4 to obtain the number n second column.
Thus, $\frac{15 \times 24}{4} = 90$
$\frac{28 \times 16}{4} = 112$
Hence, the missing value is: $\frac{17 \times 16}{4} = 68$

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60	55	76	66	58	72	68	60	55	68	55	58
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$\begin{matrix} 95 & 92 & 91 & 90 & 88 & 82 & 86 & 87 & 87 & 88 & 70 & 72 & 76 & 77 & 77 79 & 79 & 79 & 78 & 78 & 68 & 67 & 67 & 66 & 65 & 62 & 62 & 62 & 62 & 64 58 & 59 & 60 & 60 & 60 & 60 & 61 & 62 & 62 & 62 & 55 & 55 & 55 & 56 & 57 54 & 53 & 52 & 52 & 50 \end{matrix}$

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58	60	72	68	58	55	58	72	55	68	66	60
60	55	76	66	58	72	68	60	55	68	55	58
62	66	72	58	60	68	55	58	65	72	68

58	60	72	68	58	55	58	72	55	68	66	60
60	55	76	66	58	72	68	60	55	68	55	58
62	66	72	58	60	68	55	58	65	72	68

159024281121617....16

The correct option is D 68Multiply the numbers in first and third column and divide by 4 to obtain the number n second column.Thus, 15×244=9028×164=112Hence, the missing value is: 17×164=68

$\begin{matrix} 15 & 90 & 24 28 & 112 & 16 17 & . . . . & 16 \end{matrix}$

The correct option is D $68$
Multiply the numbers in first and third column and divide by 4 to obtain the number n second column.
Thus, $\frac{15 \times 24}{4} = 90$
$\frac{28 \times 16}{4} = 112$
Hence, the missing value is: $\frac{17 \times 16}{4} = 68$

58	60	72	68	58	55	58	72	55	68	66	60
60	55	76	66	58	72	68	60	55	68	55	58
62	66	72	58	60	68	55	58	65	72	68