$\begin{matrix} 17 & 8 & 58 10 & 5 & 35 9 & 3 & . . . . \end{matrix}$

27

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34

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54

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65

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Solution

The correct option is A $27$
Two times the number in first column an three times the number in second column is equal to the number in third column.
Thus, $2 \times 17 + 3 \times 8 = 58$
$2 \times 10 + 3 \times 5 = 35$
Hence, the missing number is: $2 \times 9 + 3 \times 3 = 27$

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