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Scalar Multiplication of a Matrix

3 23 7 5...

Question

$\begin{matrix} 3 & (23) & 7 5 & (47) & 9 6 & (. . . .) & 11 \end{matrix}$

A

68

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B

56

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C

45

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D

59

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Solution

The correct option is A 68
Multiply the number in first column and the third column and add two to obtain the number in the second column.
Thus, $23 = 7 \times 3 + 2$
$47 = 9 \times 5 + 2$
Hence, missing number is $11 \times 6 + 2 = 68$

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