$\begin{matrix} 328 & (258) & 457 146 & (. . . .) & 269 \end{matrix}$

148

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228

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196

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246

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Solution

The correct option is D 246
Two times the number obtained by subtracting the number in third column with the number in first column gives that in the second column.
Thus, $258 = 2 \times (457 - 328) = 2 \times 129 = 258$
Missing value is: $2 \times (269 - 146) = 2 \times 123 = 246$

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