Question

$\begin{array}{ccc}4& 3& 50\\ 6& 5& 122\\ 7& 9& ....\end{array}$

Answer 1

Add the first and second number of each row, square the sum, and add 1 to it. You get the last number in the row.
Formula : $(a+b{)}^2+1=c$
$4+3=7;$ $7^2$ $=49;49+1=50$
$6+4=11;$ ${11}^2$ $=121;121+1=122$
$7+9=16;$ ${16}^2$$=256;256+1=257$