$\begin{matrix} 8 & 128 & 2 4 & 1 & 64 . . . . & 32 & 256 \end{matrix}$

12

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15

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13

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16

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Solution

The correct option is D $16$
Arrange the given numbers in ascending order: $2483264128256$
All the numbers are multiples of $2$ and increase in order by multiplying by $2.$
Thus, the missing number is $16.$

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Similar questions

Q. 2, 20, 19, 12, 14 ; 3, 13, 12, 16, 15 ; 4, 14, 16, 8, 7 ; ?

Verify the following :

(i) $\frac{3}{7} \times (\frac{5}{6} + \frac{12}{13}) = (\frac{3}{7} \times \frac{5}{6}) + (\frac{3}{7} \times \frac{12}{13})$
(ii) $\frac{- 15}{4} \times (\frac{3}{7} + \frac{- 12}{5}) = (\frac{- 15}{4} \times \frac{3}{7}) + (\frac{- 15}{4} \times \frac{- 12}{5})$
(iii) $(\frac{- 8}{3} + \frac{- 13}{12}) \times \frac{5}{6} = (\frac{- 8}{3} \times \frac{5}{6}) + (\frac{- 13}{12} \times \frac{5}{6})$
(iv) $\frac{- 16}{7} \times (\frac{- 8}{9} + \frac{- 7}{6}) = (\frac{- 16}{7} \times \frac{- 8}{9}) + (\frac{- 16}{7} \times \frac{- 7}{6})$

What should be subtracted from 12a – 16b to obtain -a – b?

\begin{matrix} 15 & (120) & 16 12 & (108) & 18 13 & (. . . .) & 14 \end{matrix}

The marks of

20

students in a test were as follows:

5, 6, 8, 9, 10, 11, 11, 12, 13, 13, 14, 14, 15, 15, 15, 16, 16, 18, 19, 20

The mode is

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812824164....32256

The correct option is D 16Arrange the given numbers in ascending order: 2 4 8 32 64 128 256All the numbers are multiples of 2 and increase in order by multiplying by 2.Thus, the missing number is 16.

$\begin{matrix} 8 & 128 & 2 4 & 1 & 64 . . . . & 32 & 256 \end{matrix}$

The correct option is D $16$
Arrange the given numbers in ascending order: $2483264128256$
All the numbers are multiples of $2$ and increase in order by multiplying by $2.$
Thus, the missing number is $16.$