Question

$\begin{array}{ccc}8& 4& \left(28\right)\\ 12& 3& \left(33\right)\\ 11& 6& (....)\end{array}$

• A. 48
• B. 36
• C. 24
• D. 60
  

Answer 1

The correct option is D 60

Multiply the number in first two columns and subtract the number in second column will give the resultant number in the third column.
Thus, $8\times 4-4=28$
$12\times 3-3=33$
$11\times 6-6=60$