Question

$\begin{array}{ccc}8& 4& \left(288\right)\\ 5& 4& \left(162\right)\\ 3& 5& (....)\end{array}$

• A. 128
• B. 96
• C. 64
• D. 116

Answer 1

The correct option is A 128

Multiply the sum of numbers in first two columns with the twice the sum of numbers in the first two columns to get the number in the third column.
Thus, $(8+4)\times 2\times (8+4)=288$
$(5+4)\times 2\times (5+4)=162$
Hence, the missing number is:
$(3+5)\times 2\times (5+3)=128$