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Byju's Answer
Standard XII
Chemistry
Sigma Bond and Pi Bond
CH2 - CH -...
Question
C
H
2
−
C
H
−
C
H
−
C
H
−
C
H
2
|
|
|
|
|
O
H
O
H
O
H
O
H
O
H
The number of configurational isomers of the above-given compound is:
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Solution
As we know, the number of optically active forms is
=
a
=
2
n
−
1
−
2
n
−
1
2
;
a
=
2
3
−
1
−
2
3
−
1
2
=
4
−
2
=
2
,
where n is the number of chiral centres, which is 3 here.
The number of meso forms, m is
=
2
3
−
1
2
=
2
1
=
2
.
The total number of configurational isomers is,
a
+
m
=
2
+
2
=
4
.
So, the correct answer is 4
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1
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