wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

CH2CHCHCHCH2|||||OHOHOHOHOH

The number of configurational isomers of the above-given compound is:

Open in App
Solution

As we know, the number of optically active forms is =a=2n12n12;a=2312312=42=2,
where n is the number of chiral centres, which is 3 here.
The number of meso forms, m is =2312=21=2.
The total number of configurational isomers is, a+m=2+2=4.

So, the correct answer is 4

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
VBT and Orbital Overlap
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon