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Question

CH2CHCHCHCH2|||||OHOHOHOHOH

The number of configurational isomers of the above-given compound is:

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Solution

As we know, the number of optically active forms is =a=2n12n12;a=2312312=42=2,
where n is the number of chiral centres, which is 3 here.
The number of meso forms, m is =2312=21=2.
The total number of configurational isomers is, a+m=2+2=4.

So, the correct answer is 4

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