$\begin{matrix} C H_{3} O - C H = C H - N O_{2} & 1 C H_{2} = C H - N O_{2} & 2 C H_{2} = C H - C l & 3 C H_{2} = C H_{2} & 4 \end{matrix}$

Which of the following is the correct order of bond length among these compounds?

1 > 2 > 3 > 4

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4 > 3 > 2 > 1

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1 > 3 > 2 > 4

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2 > 3 > 1 > 4

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Solution

The correct option is A
1 > 2 > 3 > 4

$e^{-}$ withdrawing will decrease the double bond character

Suggest Corrections

Similar questions

C H_{3} - C H_{3}, C H_{2} = C H_{2}

C H \equiv C H

(1) C H_{3} C H_{2} C H_{2} C H_{2} O H

(2) C H_{3} C H_{2} C H_{2} C H O

(3) C H_{3} C H_{2} C H_{2} C O O H

C H_{3} C H_{2} C H_{2} C H_{2} O H

C H_{3} C H_{2} C H_{2} C H O

C H_{3} C H_{2} C H_{2} C O O H

(1) C H_{3} C H = C H_{2} + H B R - ---------- \to C H_{3} C H_{2} C H_{2} - B r

(2) C H_{3} C H = C H_{2} + C I_{2} - --------- \to C H_{3} C H (C l) C H_{3}

(3) C H_{3} C H = C H_{2} + H C I - ---------- \to C l - C H_{2} C H = C H_{2}

(4) C H_{3} C H_{3} + C l_{2} h r - \to C I - C H_{2} C H = C H_{2}

S_{N} 1

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