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Byju's Answer
Standard XII
Mathematics
Limit
lim x 1 1...
Question
l
i
m
x
−
−
→
1
(
1
x
−
1
−
2
x
2
−
1
)
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Solution
1
x
−
1
−
2
(
x
+
1
)
(
x
−
1
)
=
x
+
1
−
2
(
x
+
1
)
(
x
−
1
)
=
x
−
1
(
x
+
1
)
(
x
−
1
)
=
1
x
+
1
lim
x
−
1
1
x
+
1
=
1
2
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