Question

$\begin{array}{c}AB\\ \times 6\\ BBB\end{array}$

• A. 100 × 1 + 10 × 2 + 8
• B. 100 × 1 + 10 × 2 + 5
• C. 100 × 1 + 10 × 8 + 2
• D. 100 × 2 + 10 × 1 + 8

Answer 1

The correct option is A

100 × 1 + 10 × 2 + 8

If we consider B = 1 ; then A1 $\times$ 6 = 111 , which is not possible,since no multiple of 6 ends with 1 , therefore this is not possible
If we consider B = 2 ; then A2 $\times$ 6 = 222
When we consider the ten's place , we have A6 + 1 = 22
A6 = 21 ( which is not divisible by 6)
Hence B $\ne$ 2

If we consider B = 3 , we have A3 $\times$ 6 = 333 ; No multiple of 6 ends with 3 , therefore this is not possible

If we consider B = 4 , we have A4$\times$ 6 = 444,
In the units's place , we have 4 $\times$ 6 = 24, hence 4 in the units place and carry over 2 to the ten's place

In the ten's place , we have A$\times$ 6 + 2 = 44 ; A6 = 42 $\therefore$ A = 7

Hence the values of A and B are 7 and 4 respectively