$\begin{matrix} A B + A B + B B B \end{matrix}$
A=_ ;B=_

Open in App

Solution

B + B + B = B → on adding B three times, we are getting B again at unit's place. This is only possible if B is either 0 or 5.

0 + 0 + 0 = 0 and 5 + 5 + 5 = 15;
So, 1 is carry. The answer is BB i.e., 55.

∴ Now we have

1 + A + A = 5

2A = 4

A = 2

Suggest Corrections

Similar questions

$a b + 2 a b$ is equal to

a b

b b c

c

a b

a b

b

50

A, A B, B, A, O, A B, O, O, A, A B, B, A, O, A B, O, O, A, B, A, O, A B, O, O, A, A B,

B, O, A B, O, B, A, O, A B, O, O, A, A B, B, A, O, A B, O, A, A B, B, A, O, A B, O, O

$a b \times a \times a b \times b$ equals

\sqrt{a b + (a - b) \sqrt{a b + (a - b) \sqrt{a b + (a - b) \sqrt{a b + . . .}}}}

Join BYJU'S Learning Program