AA- BB - AAAA - A6AA- - B-

The correct option is A A = 3, B = 1 ∴ We have , AA × 11 AA AA A6A A + A = 6; 2A = 6; A = 3 ∴ A = 3, B = 1 ...

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Question

$\begin{matrix} A A \times B B A A A A A 6 A \end{matrix}$
A=_; B=__

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A = 6, B = 2

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A = 2, B = 6

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