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Question

Find the digits A and B for the given multiplication to hold true.
AA × BB AA= AA 0 A6A


A

3

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B
1
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C
A = 6, B = 2
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D
A = 2, B = 6
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Solution

The correct option is A

3


From the given multiplication we can deduce,

A + A = 6
2A = 6;
A = 3
Also, A x B = A. This is possible only if B = 1
Hence A = 3 and B = 1


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