Question

$\begin{array}{cc}\underset{–}{ListI}& \underset{–}{ListII}\\ 2& 3\\ 4& 5\\ 7& 6\end{array}$
One number is to be selected at random from each of the lists above. What is the probability that both of the numbers selected will be less than $5$?

• A. $\frac{1}{9}$
• B. $\frac{2}{9}$
• C. $\frac{1}{3}$
• D. $\frac{4}{9}$
• E. $\frac{5}{9}$

Answer 1

Answer: (B)

$\frac{2}{9}$

Total number of ways in which we can select one number from each set is $9$.

among those the selection of numbers $(2,3)$ and $(4,3)$ results in both numbers less than 5.

So the probability that both numbers is less than $5$ is $2/9$.