- 6i -3i 1- 4 3i -1- 20 3 i -x-iy

The correct option is D 0,0Given, [ 6i amp; 3i amp;1; 4 amp;3i amp; 1; 20 amp;3 amp;i ]=x+iy 6i[ 3i amp; 1; 3 amp;i ] ...

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Square Matrix

[ 6i -3i 1; ...

Question

$⎛ ⎜ ⎝ \begin{matrix} 6 i & - 3 i & 1 4 & 3 i & - 1 20 & 3 & i \end{matrix} ⎞ ⎟ ⎠ = x + i y$

3,1

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1,3

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0,3

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0,0

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Solution

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Similar questions

∣ ∣ ∣ ∣ \begin{matrix} 6 i & - 3 i & 1 2 & 3 & i 4 & 3 i & - 1 \end{matrix} ∣ ∣ ∣ ∣ = x + i y

∣ ∣ ∣ ∣ \begin{matrix} 6 i & - 3 i & 1 4 & 3 i & - 1 20 & 3 & i \end{matrix} ∣ ∣ ∣ ∣ = x + i y

∣ ∣ ∣ ∣ \begin{matrix} 6 i & - 3 i & 1 4 & 3 i & - 1 20 & 3 & i \end{matrix} ∣ ∣ ∣ ∣ = x + i y

2 i^{2} + 6 i^{3} + 3 i^{16} - 6 i^{19} + 4 i^{25} = x + i y

(x, y) =

∣ ∣ ∣ ∣ \begin{matrix} 6 i & - 3 i & 1 4 & 3 i & - 1 20 & 3 & i \end{matrix} ∣ ∣ ∣ ∣ = x + i y,

i = \sqrt{- 1}

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