1 1 1 1 1 - x 1 1 1 1 -y is equal to

The correct option is B xy Let = 1 #160; amp; 1 amp; 1 #160;1 amp; 1 + x #160; amp; 1 1 #160; amp; 1 amp; 1 +y Applyi ...

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Properties of Determinants

1 1 1 1...

Question

$∣ ∣ ∣ ∣ \begin{matrix} 1 & 1 & 1 1 & 1 + x & 1 1 & 1 & 1 + y \end{matrix} ∣ ∣ ∣ ∣$ is equal to

x + y

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x y

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x - y

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1 + x + y

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Solution

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Similar questions

Δ = ∣ ∣ ∣ ∣ \begin{matrix} 1 & 1 & 1 1 & 1 + x & 1 1 & 1 & 1 + y \end{matrix} ∣ ∣ ∣ ∣

x \neq 0, y \neq 0

Δ

D = ∣ ∣ ∣ ∣ \begin{matrix} 1 & 1 & 1 1 & 1 + x & 1 1 & 1 & 1 + y \end{matrix} ∣ ∣ ∣ ∣

x \neq 0, y \neq 0

D

D =

∣ ∣ ∣ ∣ \begin{matrix} 1 & 1 & 1 1 & 1 + x & 1 1 & 1 & 1 + y \end{matrix} ∣ ∣ ∣ ∣

x \neq 0, y \neq 0,

∣ ∣ ∣ ∣ \begin{matrix} 1 & 1 & 1 1 & 1 + x & 1 1 & 1 & 1 + y \end{matrix} ∣ ∣ ∣ ∣ =

A = ∣ ∣ ∣ ∣ \begin{matrix} 1 & 1 & 1 1 & 1 + x & 1 1 & 1 & 1 + y \end{matrix} ∣ ∣ ∣ ∣ =

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