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B
0,1
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C
1, 3
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D
2, 0
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Solution
The correct option is A -1, 2 ∣∣
∣∣14201−2512x5x2∣∣
∣∣=0 r1→r1−r2 and r3→r3−r2 ∣∣
∣∣06151−2502x+25x2−5∣∣
∣∣ =−(6(5x2−5)−15(2x+2)) =−(30x2−30−30x−30) =30(−x2+x+2) So, x2−x−2=0 x=−1,2