1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XIII
Mathematics
Evaluation of a Determinant
1 a b-a ...
Question
∣
∣ ∣
∣
1
a
b
−
a
1
c
−
b
−
c
1
∣
∣ ∣
∣
=
A
1
+
a
2
+
b
2
+
c
2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
1
−
a
2
+
b
2
+
c
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1
+
a
2
+
b
2
−
c
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1
+
a
2
−
b
2
+
c
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is
A
1
+
a
2
+
b
2
+
c
2
∣
∣ ∣
∣
1
a
b
−
a
1
c
−
b
−
c
1
∣
∣ ∣
∣
=
1
(
1
+
c
2
)
−
a
(
−
a
+
b
c
)
+
b
(
a
c
+
b
)
=
1
+
a
2
+
b
2
+
c
2
.
Suggest Corrections
0
Similar questions
Q.
Prove that ,
⎛
⎜
⎝
1
a
b
−
a
1
c
−
b
−
c
1
⎞
⎟
⎠
=
1
+
a
2
+
b
2
+
c
2
Q.
(1𝑥𝑎−)1(𝑎−𝑐). (1𝑥𝑏−𝑐)1(𝑏−𝑎). (1𝑥𝑐−𝑎)1(𝑐−𝑏)
Q.
If
1
A
B
+
C
C
A
=
2
9
5
, then the value of
B
is
Q.
The value of the determinant
∣
∣ ∣
∣
1
a
b
+
c
1
b
c
+
a
1
c
a
+
b
∣
∣ ∣
∣
is
Q.
Write the value of
tan
-
1
a
b
-
tan
-
1
a
-
b
a
+
b
.
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Evaluation of Determinants
MATHEMATICS
Watch in App
Explore more
Evaluation of a Determinant
Standard XIII Mathematics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app