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Question

∣∣ ∣∣1ab−a1c−b−c1∣∣ ∣∣=

A
1+a2+b2+c2
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B
1a2+b2+c2
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C
1+a2+b2c2
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D
1+a2b2+c2
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Solution

The correct option is A 1+a2+b2+c2
∣ ∣1aba1cbc1∣ ∣=1(1+c2)a(a+bc)+b(ac+b)=1+a2+b2+c2.

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