beginvmatrix 1- i - 1- i - i 11-i - i - 1-i i - 1- i - 1- ilend vmatrix -1 A- -4-7 iB- 4-7 iC- 3-7 iD- 7-4 i

The correct option is B 4+7iΔ =(2+i) 1 amp; 1 amp; i 1 amp; 1+2i amp; 1+i 1 amp; 2 amp; 1 i =(2+i) 0 amp; 2i amp; 1 0 amp; 1 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Evaluation of a Determinant

beginvmatrix ...

Question

$∣ ∣ ∣ ∣ \begin{matrix} 1 + i & 1 - i & i 1 - i & i & 1 + i i & 1 + i & 1 - i \end{matrix} ∣ ∣ ∣ ∣ =$

-4-7i

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4+7i

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3+7i

No worries! We‘ve got your back. Try BYJU‘S free classes today!

7+4i

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

7 - 5 i

\sqrt{3} - i

\sqrt{3} + \sqrt{2 i}

3

- 8 + 15 i

1 + i

- 3 (l - i)

1 + i \sqrt{3}

- 4 - 4 i

(1 + 2 i)^{2} (1 - i)

(1 + i) (1 + 2 i)

\frac{3 + 2 i}{- 2 + i}

\frac{1}{(2 + i)^{2}}

\frac{1 - i}{1 + i}

\frac{(2 + i)^{3}}{2 + 3 i}

\frac{(1 + i) (1 + \sqrt{3} i)}{1 - i}

\frac{2 + 3 i}{4 + 5 i}

\frac{(1 - i)^{3}}{1 - i^{3}}

(1 + 2 i)^{- 3}

\frac{3 - 4 i}{(4 - 2 i) (1 + i)}

(\frac{1}{1 - 4 i} - \frac{2}{1 + i}) (\frac{1 - 4 i}{5 + i})

\frac{5 + \sqrt{2} i}{1 - 2 \sqrt{i}}

If 3X + 2Y = I and 2X - Y = O, where I and O are unit and null matrices of order 3 respectively, then

∣ ∣ ∣ ∣ \begin{matrix} 1 + i & 1 - i & 1 1 - i & i & 1 + i i & 1 + i & 1 - i \end{matrix} ∣ ∣ ∣ ∣

∣ ∣ ∣ ∣ \begin{matrix} 1 + i & 1 - i & i 1 - i & i & 1 + i i & 1 + i & 1 - i \end{matrix} ∣ ∣ ∣ ∣ =

Join BYJU'S Learning Program