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Question

∣∣ ∣ ∣∣a2+x2ab−cxac+bxab+cxb2+x2bc−axac−bxbc+axc2+x2∣∣ ∣ ∣∣=

A
∣ ∣xbcaxcabx∣ ∣2
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B
∣ ∣xbcaxcabx∣ ∣2
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C
∣ ∣xcbcxabax∣ ∣2
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D
∣ ∣xcbcxabax∣ ∣2
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Solution

The correct options are
C ∣ ∣xcbcxabax∣ ∣2
D ∣ ∣xcbcxabax∣ ∣2
Let D=∣ ∣xcbcxabax∣ ∣
Cofactors of 1st Row of D are
x2+a2,ab+cx,acbx
Cofactor of 2nd Row of D are
abcx,x2+b2,ax+bc
and cofactors of 3rd row of D are
ax+bx,bcax,x2+c2
Determinant of cofactors of D is
Dc=∣ ∣ ∣x2+a2ab+cxacbxabcxx2+b2ax+bcac+bxbcaxx2+c2∣ ∣ ∣
=∣ ∣ ∣a2+x2abcxac+bxab+cxb2+x2bcaxacbxax+bcc2+x2∣ ∣ ∣ (Rows interchanging into columns)
=D2
=∣ ∣xcb2cxabax∣ ∣2
(Dc=D2, D is third order determinant)
Hence,
∣ ∣ ∣a2+x2abcxac+bxab+cxb2+x2bcaxacbxax+bcc2+x2∣ ∣ ∣=∣ ∣xcbcxabax∣ ∣2


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