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Question

∣ ∣a+babaa+ccbcb+c∣ ∣ is equal to.

A
4abc
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B
abc
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C
a2b2c2
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D
4a2bc
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Solution

The correct option is B 4abc
∣ ∣a+babaa+ccbcb+c∣ ∣=∣ ∣2(a+b)2(a+c)2(b+c)aa+ccbcb+c∣ ∣,R1R1+R2+R3
=2∣ ∣a+ba+cb+caa+ccbcb+c∣ ∣=2∣ ∣b0baa+ccbcb+c∣ ∣,R1R1R2
=2b∣ ∣101ababbcb+c∣ ∣,R2R2R3
=2b[a(b+c)+bc+acbcab], Expand along first row
=2b(2ac)=4abc

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