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Question

∣ ∣ ∣b2abbcbcacaba2abb2abbcaccaaba2∣ ∣ ∣=

A
abc(a+b+c)
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B
3a2b2c2
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C
0.0
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D
None of these
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Solution

The correct option is C 0.0
Δ=(ba)(ba).∣ ∣bbccaabbccaa∣ ∣=(ab)2∣ ∣bbcaabcca∣ ∣=0,[by C2C2+C3].

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