4x 6X-2 8X-1 6X 9X-3 12X 8X 12X 16X-2 - 0- then x is equal to

The correct option is A X = 0 2 4x amp; 6x+2 amp; 8x+1 6x amp; 9x+3 amp; 12x 4x amp; 6x amp; 8x+1 R_1→ R_1 R_3→ 2 0 amp ...

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Skew Symmetric Matrix

4x 6X+2 8...

Question

$∣ ∣ ∣ ∣ ∣ ∣ \begin{matrix} \begin{matrix} 4 x & 6 X + 2 & 8 X + 1 6 X & 9 X + 3 & 12 X 8 X & 12 X & 16 X + 2 \end{matrix} \end{matrix} ∣ ∣ ∣ ∣ ∣ ∣$ = 0, then x is equal to

X = 0

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X = -11

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x = 97

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X = -

\frac{11}{97}

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f (x) = ⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩ \begin{matrix} (1 + a x)^{\frac{1}{x}}, if x < 0 b, if x = 0 \frac{(x + c)^{\frac{1}{3}} - 1}{(x + 1)^{\frac{1}{2}} - 1}, if x > 0 \end{matrix}

x = 0

Will the value of $11 x$ for $x = - 5$ be greater than $11$ or less than $11 ?$ Explain.

x^{2} - 11 x + a = 0

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a

{\begin{matrix} 1 + x^{3}, x < 0 x^{2} - 1, x \geq 0 \end{matrix}

{\begin{matrix} (x - 1)^{1 / 3}, x < 0 (x + 1)^{1 / 2}, x \geq 0 \end{matrix}

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