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Question

∣ ∣ ∣(ax+ax)2(axax)21(bx+bx)2(bxbx)21(cx+cx)2(cxcx)21∣ ∣ ∣ is equal to

A
0
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B
2abc
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C
a2b2c2
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D
None of these
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Solution

The correct option is C 0
Let Δ=∣ ∣ ∣(ax+ax)2(axax)21(bx+bx)2(bxbx)21(cx+cx)2(cxcx)21∣ ∣ ∣

Put x=0 in the given determinant, we get

Δ=∣ ∣ ∣(1+1)2(11)21(1+1)2(11)21(1+1)2(11)21∣ ∣ ∣

=∣ ∣401401401∣ ∣

=0

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