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Question

∣ ∣ ∣x2+xx+1x+2x2+3x13x3x3x2+2x+32x12x1∣ ∣ ∣=Ax+B where A and B are determinants of order 3. Then A+2B is equal to

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Solution

C1C1C2C3C3C2=∣ ∣ ∣x21x+11x213x3x2+42x10∣ ∣ ∣
=∣ ∣ ∣x2x+11x23x3x22x10∣ ∣ ∣+∣ ∣1x+1113x342x10∣ ∣=x∣ ∣xx+11x3x3x2x10∣ ∣+∣ ∣1x+1113x342x10∣ ∣
=Ax+B
A+2B=∣ ∣x2x+11x23x3x+82x10∣ ∣
R2R2+3R1A+2B=∣ ∣x2x+114x86x+30x+82x10∣ ∣
A+2B=(x2)×3(2x+1)(x+1)×4(x2)
=(x2)(6x+34x4)=(x2)(2x1)

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