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Question

∣ ∣y+zxxyz+xyzzx+y∣ ∣ equals

A
x2y2z2
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B
4x2y2z2
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C
xyz
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D
4xyz
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Solution

The correct option is D 4xyz
Let Δ=∣ ∣y+zxxyz+xyzzx+y∣ ∣
Applying Δ=∣ ∣y+zxxyz+xyzzx+y∣ ∣
Δ=∣ ∣y+zxxzzyxyzxy∣ ∣=(y+z)(yz(yx)(zx))x(yz+y(yx))+x(yz+z(zx))=(y+z)(yzyz+yx+xzx2)x(yzyx+y2)+x(xz+yz+z2)=y2x+y2xx2y+y2x+z2xx2z+y2xy2x+x2yz2x+x2z+y2x=4xyz

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