The correct option is D 4xyz
Let Δ=∣∣
∣∣y+zxxyz+xyzzx+y∣∣
∣∣
Applying Δ=∣∣
∣∣y+zxxyz+xyzzx+y∣∣
∣∣
Δ=∣∣
∣∣y+zxx−zzy−x−yz−xy∣∣
∣∣=(y+z)(yz−(y−x)(z−x))−x(−yz+y(y−x))+x(yz+−z(z−x))=(y+z)(yz−yz+yx+xz−x2)−x(−yz−yx+y2)+x(xz+yz+−z2)=y2x+y2x−x2y+y2x+z2x−x2z+y2x−y2x+x2y−z2x+x2z+y2x=4xyz