Question

Below, a circuit containing 6 resistors (not necessarily the same) is pictured. If the reading on ammeter 1 is 10.0 A, the reading on ammeter 2 is 3.0 A, and the reading on ammeter 3 is 6.0 A, what is the current through resistors 2, 4 and 6?

Answer 1

The total current in the circuit will be shown by ammeter 1 , that is $I=10.0A$ ,now this current is divided in branch 5 and 6 , in resistor 5 the current is $I_5=6.0A$ ,

now by Kirchhoff's law $I=I_5+I_6$ ,

or $I_6=I-I_5=10.0-6.0=4A$ ,

through resistor 4 , total current is passing , that is $I_4=I=10.0A$

again by Kirchhoff's law , for current in resistor 2 ,

$I=I_3+I_2$ ,

or $I_2=I-I_3=10.0-3.0=7A$