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Standard XII

Chemistry

Relative Lowering of Vapour Pressure

Benzene and t...

Question

Benzene and toluene form nearly an ideal solution. At 300K, P°toluene = 32.06 mm Hg and P°benzene = 103.01 mm Hg.
A liquid mixture is composed of 3 moles of toluene and 2 moles of benzene. At what pressure does the LAST trace of liquid disappear?

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Solution

$P_{T o t} = P_{A}^{0} X_{A} + P_{B}^{0} X_{B} H e r e c o n s i d e r A a s t o l u n e a n d B a s b e n z e n e P_{T o t} = 32.06 \times \frac{3}{5} + 103.01 \times \frac{2}{5} = 19.236 + 41.204 = 60.44 m m H g A t 60.44 p r e s s u r e t h e l a s t t r a c e o f l i q u i d d i s a p p e a r .$

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Benzene and toluene form nearly an ideal solution. At 300K, P°toluene = 32.06 mm Hg and P°benzene = 103.01 mm Hg. A liquid mixture is composed of 3 moles of toluene and 2 moles of benzene. At what pressure does the LAST trace of liquid disappear?

PTot = PA0XA + PB0XBHere consider A as tolune and B as benzenePTot = 32.06 × 35 + 103.01× 25 = 19.236 + 41.204 = 60.44 mm Hg At 60.44 pressure the last trace of liquid disappear.

Benzene and toluene form nearly an ideal solution. At 300K, P°toluene = 32.06 mm Hg and P°benzene = 103.01 mm Hg.
A liquid mixture is composed of 3 moles of toluene and 2 moles of benzene. At what pressure does the LAST trace of liquid disappear?